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. We initially show that x mod n = a mod n. It is generally legitimate that (a + bn) mod n = a mod n for all integers b; Consequently, This is often correct also in The actual scenario when b = − ⌊ a − d n ⌋ textstyle b=-!leftlfloor frac a-d n suitablerfloor 作为一个在医疗行业从业十年,自己也是做过近视眼手术的人�